MYP 3 · Maths

NUMBER

Natural numbers

QUESTION 1 [4 marks] — Criterion A Medium
A stadium has seats numbered consecutively from 1. Section A has seats 1 to 248, Section B continues from where A ends.
a. If Section B has 315 seats, what is the number of its last seat?
[2]
Show Solution
Section B: seats $249$ to $249+315-1=563$. Last seat number $=563$.
b. A seat is numbered 400. Which section is it in, and what position within that section (e.g. the 1st seat of the section, 2nd, etc.)?
[2]
Show Solution
Since $249 \le 400 \le 563$, seat 400 is in Section B, at position $400-249+1=152$ (the 152nd seat of Section B).
QUESTION 2 [4 marks] — Criterion A Medium
Evaluate, showing full working: (a) the sum of all natural numbers from 1 to 50; (b) the sum of all even natural numbers from 2 to 50.
a. Find the sum of all natural numbers from 1 to 50, using the fact that pairing the first and last, second and second-last, etc. all give the same sum.
[2]
Show Solution
Pairing gives 25 pairs, each summing to $1+50=51$. Total $=25\times51=1275$.
b. Find the sum of all even natural numbers from 2 to 50, using a similar pairing approach.
[2]
Show Solution
There are 25 even numbers (2 to 50). Pairing first+last: $2+50=52$, giving $12.5$ pairs... more directly: sum $= 2(1+2+\cdots+25) = 2\times\frac{25\times26}{2}=650$.
QUESTION 3 [6 marks] — Criterion B Medium
Investigate the pattern in the sum of the first $n$ natural numbers.
a. Calculate the sum of the first 3, first 4, and first 5 natural numbers.
[2]
Show Solution
$1+2+3=6$. $1+2+3+4=10$. $1+2+3+4+5=15$.
b. Compare each sum to the formula $\frac{n(n+1)}{2}$ for the corresponding $n$. Does it match?
[2]
Show Solution
$n=3$: $\frac{3\times4}{2}=6$ ?. $n=4$: $\frac{4\times5}{2}=10$ ?. $n=5$: $\frac{5\times6}{2}=15$ ?. All match.
c. Use the formula to predict the sum of the first 100 natural numbers, then explain how confident you are in this prediction.
[2]
Show Solution
$$\frac{100\times101}{2}=5050$$ Since the formula matched exactly for every tested case, and it is a well-known proven result (Gauss's method), this prediction can be trusted with high confidence.
QUESTION 4 [5 marks] — Criterion C Medium
Explain, using a diagrammatic or pairing argument (in words), why the sum of the first $n$ natural numbers equals $\frac{n(n+1)}{2}$.
a. Describe the pairing method: write the sum forwards and backwards, add corresponding terms, and explain what you notice.
[3]
Show Solution
Writing $S = 1+2+\cdots+n$ and also $S=n+(n-1)+\cdots+1$, then adding term-by-term: each pair sums to $(n+1)$, and there are $n$ such pairs, giving $2S=n(n+1)$.
b. Complete the explanation by solving for $S$.
[2]
Show Solution
$$S = \frac{n(n+1)}{2}$$
QUESTION 5 [5 marks] — Criterion D Medium
A charity is stacking donated cans into a triangular display: 1 can on top, 2 in the next row, 3 in the row below that, and so on.
a. If the display has 12 rows, find the total number of cans, using the natural number sum formula.
[2]
Show Solution
$$\frac{12\times13}{2}=78 \text{ cans}$$
b. The charity has 100 cans donated. What is the maximum number of complete rows they can build, and how many cans will be left over?
[3]
Show Solution
Testing: 13 rows needs $\frac{13\times14}{2}=91$ cans. 14 rows needs $\frac{14\times15}{2}=105$ cans (too many). So 13 complete rows can be built, using 91 cans, leaving $100-91=9$ cans left over.
QUESTION 6 [6 marks] — Criterion A Hard
A theatre has seats arranged in rows. Row 1 has 18 seats, and each subsequent row has 3 more seats than the previous row. The theatre has 22 rows.
a. Find the number of seats in Row 22.
[2]
Show Solution
$$u_{22} = 18+(22-1)(3) = 18+63=81 \text{ seats}$$
b. The theatre manager wants to know the total seating capacity, but also needs to reserve the LAST 2 seats of every row for accessibility, leaving them empty. Find the total number of seats that will actually be occupied, across all 22 rows.
[4]
Show Solution
Total seats $=\frac{22}{2}(18+81)=11(99)=1089$. Reserved seats $=22\times2=44$. Occupied seats $=1089-44=1045$.
QUESTION 7 [7 marks] — Criterion B Hard
Prove, using algebra, that the sum of any 4 consecutive natural numbers is never divisible by 4.
a. Let the 4 consecutive natural numbers be $n, n+1, n+2, n+3$. Write and simplify an expression for their sum.
[2]
Show Solution
$$n+(n+1)+(n+2)+(n+3) = 4n+6$$
b. Explain, by considering the remainder when $4n+6$ is divided by 4, why this sum can NEVER be exactly divisible by 4, for ANY natural number $n$.
[3]
Show Solution
$4n+6 = 4(n+1)+2$ — this shows $4n+6$ is always 2 MORE than a multiple of 4 (i.e. it leaves remainder 2 when divided by 4), for every possible value of $n$. Since the remainder is never 0, the sum can never be exactly divisible by 4.
c. Verify this conclusion using the 4 consecutive numbers 7, 8, 9, 10.
[2]
Show Solution
Sum $=7+8+9+10=34$. $34\div4=8.5$ (remainder 2, matching the proof) — confirms 34 is not divisible by 4.
QUESTION 8 [5 marks] — Criterion C Hard
A younger student asks why $0$ is considered a 'whole number' but not always a 'natural number', and why this distinction even matters.
a. Clearly define, using precise mathematical language, the difference between the sets of Natural Numbers and Whole Numbers, and where 0 fits.
[3]
Show Solution
Let $\mathbb{N} = \{1,2,3,4,\ldots\}$ denote the natural numbers (some definitions include 0, but the traditional MYP convention excludes it), and let $W=\{0,1,2,3,\ldots\}$ denote the whole numbers. The key distinction is that $0 \in W$ but $0 \notin \mathbb{N}$ under this convention — whole numbers include everything natural numbers do, PLUS zero.
b. Explain, with a concrete real-world example, WHY this distinction can matter practically (e.g. why counting something might exclude zero, but measuring something might need to include it).
[2]
Show Solution
Example: if you're COUNTING the number of students absent today, the answer must be a natural number if at least someone is being 'counted' as present in a meaningful group sense in some contexts — but more clearly, if you're recording a BANK BALANCE or TEMPERATURE, zero is a completely valid and meaningful value, which is why whole numbers (including 0) are needed there, while purely 'counting' contexts (like counting people in a room, which logically starts from 1 if the room isn't empty) sometimes naturally align with natural numbers.
QUESTION 9 [7 marks] — Criterion D Hard
A city's public transport authority is planning a new bus route. Data shows the number of daily riders has followed a pattern: 240 riders in Week 1, increasing by exactly 35 riders each subsequent week, for the first 8 weeks of operation.
a. Model the number of riders in Week $n$ (for $1\le n\le8$) using an arithmetic formula, and predict the ridership in Week 8.
[3]
Show Solution
$u_n = 240+(n-1)(35)$. Week 8: $u_8=240+7(35)=240+245=485$ riders.
b. The authority wants to predict ridership in Week 20 using the SAME linear model. Calculate this prediction, then critically evaluate whether extending a linear (constant increase) model this far into the future is realistic for real-world ridership growth, identifying at least one limitation of the model.
[4]
Show Solution
$u_{20}=240+19(35)=240+665=905$ riders. This linear extrapolation is likely UNREALISTIC over such a long timeframe — real ridership growth typically slows and plateaus as it approaches the practical capacity of the route/buses, is affected by seasonal variation, and cannot increase forever at a constant rate. The model is likely only valid for the initial growth phase, not for long-term prediction.
QUESTION 10 [6 marks] — Criterion A Hard
A theatre has seats arranged in rows. Row 1 has 18 seats, and each subsequent row has 3 more seats than the previous row. The theatre has 22 rows.
a. Find the number of seats in Row 22.
[2]
Show Solution
$$u_{22} = 18+(22-1)(3) = 18+63=81 \text{ seats}$$
b. The theatre manager wants to know the total seating capacity, but also needs to reserve the LAST 2 seats of every row for accessibility, leaving them empty. Find the total number of seats that will actually be occupied, across all 22 rows.
[4]
Show Solution
Total seats $=\frac{22}{2}(18+81)=11(99)=1089$. Reserved seats $=22\times2=44$. Occupied seats $=1089-44=1045$.
QUESTION 11 [7 marks] — Criterion B Hard
Prove, using algebra, that the sum of any 4 consecutive natural numbers is never divisible by 4.
a. Let the 4 consecutive natural numbers be $n, n+1, n+2, n+3$. Write and simplify an expression for their sum.
[2]
Show Solution
$$n+(n+1)+(n+2)+(n+3) = 4n+6$$
b. Explain, by considering the remainder when $4n+6$ is divided by 4, why this sum can NEVER be exactly divisible by 4, for ANY natural number $n$.
[3]
Show Solution
$4n+6 = 4(n+1)+2$ — this shows $4n+6$ is always 2 MORE than a multiple of 4 (i.e. it leaves remainder 2 when divided by 4), for every possible value of $n$. Since the remainder is never 0, the sum can never be exactly divisible by 4.
c. Verify this conclusion using the 4 consecutive numbers 7, 8, 9, 10.
[2]
Show Solution
Sum $=7+8+9+10=34$. $34\div4=8.5$ (remainder 2, matching the proof) — confirms 34 is not divisible by 4.
QUESTION 12 [5 marks] — Criterion C Hard
A younger student asks why $0$ is considered a 'whole number' but not always a 'natural number', and why this distinction even matters.
a. Clearly define, using precise mathematical language, the difference between the sets of Natural Numbers and Whole Numbers, and where 0 fits.
[3]
Show Solution
Let $\mathbb{N} = \{1,2,3,4,\ldots\}$ denote the natural numbers (some definitions include 0, but the traditional MYP convention excludes it), and let $W=\{0,1,2,3,\ldots\}$ denote the whole numbers. The key distinction is that $0 \in W$ but $0 \notin \mathbb{N}$ under this convention — whole numbers include everything natural numbers do, PLUS zero.
b. Explain, with a concrete real-world example, WHY this distinction can matter practically (e.g. why counting something might exclude zero, but measuring something might need to include it).
[2]
Show Solution
Example: if you're COUNTING the number of students absent today, the answer must be a natural number if at least someone is being 'counted' as present in a meaningful group sense in some contexts — but more clearly, if you're recording a BANK BALANCE or TEMPERATURE, zero is a completely valid and meaningful value, which is why whole numbers (including 0) are needed there, while purely 'counting' contexts (like counting people in a room, which logically starts from 1 if the room isn't empty) sometimes naturally align with natural numbers.
QUESTION 13 [7 marks] — Criterion D Hard
A city's public transport authority is planning a new bus route. Data shows the number of daily riders has followed a pattern: 240 riders in Week 1, increasing by exactly 35 riders each subsequent week, for the first 8 weeks of operation.
a. Model the number of riders in Week $n$ (for $1\le n\le8$) using an arithmetic formula, and predict the ridership in Week 8.
[3]
Show Solution
$u_n = 240+(n-1)(35)$. Week 8: $u_8=240+7(35)=240+245=485$ riders.
b. The authority wants to predict ridership in Week 20 using the SAME linear model. Calculate this prediction, then critically evaluate whether extending a linear (constant increase) model this far into the future is realistic for real-world ridership growth, identifying at least one limitation of the model.
[4]
Show Solution
$u_{20}=240+19(35)=240+665=905$ riders. This linear extrapolation is likely UNREALISTIC over such a long timeframe — real ridership growth typically slows and plateaus as it approaches the practical capacity of the route/buses, is affected by seasonal variation, and cannot increase forever at a constant rate. The model is likely only valid for the initial growth phase, not for long-term prediction.